T323A225K015AS7200

T323A225K015AS7200
Mfr. #:
T323A225K015AS7200
制造商:
KEMET Corporation
描述:
Tantalum Capacitors - Solid Leaded 15volts 2.2uF 10%
生命周期:
制造商新产品。
数据表:
T323A225K015AS7200 数据表
交货:
DHL FedEx Ups TNT EMS
支付:
T/T Paypal Visa MoneyGram Western Union
ECAD Model:
产品属性
属性值
Tags
T323A225, T323A2, T323A, T323, T32
Service Guarantees

We guarantee 100% customer satisfaction.

Quality Guarantees

We provide 90-360 days warranty.

If the items you received were not in perfect quality, we would be responsible for your refund or replacement, but the items must be returned in their original condition.
Our experienced sales team and tech support team back our services to satisfy all our customers.

we buy and manage excess electronic components, including excess inventory identified for disposal.
Email us if you have excess stock to sell.

Email: [email protected]

Step1: Vacuum Packaging with PL
Step1:
Vacuum Packaging with PL
Step2: Anti-Static Bag
Step2:
Anti-Static Bag
Step3: Packaging Boxes
Step3:
Packaging Boxes
型号 制造商 描述 库存 价格
T323A105M025AS
DISTI # 80-T323A105M025
KEMET CorporationTantalum Capacitors - Solid Leaded 25volts 1uF 20%
RoHS: Not compliant
0
    T323A105M025AS7200
    DISTI # 80-T323A105M025-TR
    KEMET CorporationTantalum Capacitors - Solid Leaded 25volts 1uF 20%
    RoHS: Not compliant
    0
      图片 型号 描述
      T323A225K015AS7200

      Mfr.#: T323A225K015AS7200

      OMO.#: OMO-T323A225K015AS7200-1069

      Tantalum Capacitors - Solid Leaded 15volts 2.2uF 10%
      T323A225K015AS

      Mfr.#: T323A225K015AS

      OMO.#: OMO-T323A225K015AS-1069

      Tantalum Capacitors - Solid Leaded 15volts 2.2uF 10%
      可用性
      库存:
      Available
      订购:
      2000
      输入数量:
      T323A225K015AS7200的当前价格仅供参考,如果您想获得最优惠的价格,请提交查询或直接发送电子邮件至我们的销售团队[email protected]
      参考价格(美元)
      数量
      单价
      小计金额
      1
      US$0.00
      US$0.00
      10
      US$0.00
      US$0.00
      100
      US$0.00
      US$0.00
      500
      US$0.00
      US$0.00
      1000
      US$0.00
      US$0.00
      从...开始
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