KDZ18V

KDZ18V
Mfr. #:
KDZ18V
制造商:
KEC
描述:
生命周期:
制造商新产品。
数据表:
KDZ18V 数据表
交货:
DHL FedEx Ups TNT EMS
支付:
T/T Paypal Visa MoneyGram Western Union
ECAD Model:
产品属性
属性值
制造商
凯尔特人
产品分类
集成电路芯片
Tags
KDZ18V, KDZ18, KDZ1, KDZ
Service Guarantees

We guarantee 100% customer satisfaction.

Quality Guarantees

We provide 90-360 days warranty.

If the items you received were not in perfect quality, we would be responsible for your refund or replacement, but the items must be returned in their original condition.
Our experienced sales team and tech support team back our services to satisfy all our customers.

we buy and manage excess electronic components, including excess inventory identified for disposal.
Email us if you have excess stock to sell.

Email: [email protected]

Step1: Vacuum Packaging with PL
Step1:
Vacuum Packaging with PL
Step2: Anti-Static Bag
Step2:
Anti-Static Bag
Step3: Packaging Boxes
Step3:
Packaging Boxes
型号 制造商 描述 库存 价格
KDZ18V-Y-RTK/PKEC 2400
  • 1334:$0.2000
  • 112:$0.3000
  • 1:$1.0000
图片 型号 描述
KDZLVTFTR150

Mfr.#: KDZLVTFTR150

OMO.#: OMO-KDZLVTFTR150

Zener Diodes 140-160Vz(V) 2Iz(mA) AEC-Q101 Qualified
KDZTR5.1B

Mfr.#: KDZTR5.1B

OMO.#: OMO-KDZTR5-1B

Zener Diodes 5.1 to 5.7V; 40mA 1000mW
KDZVTFTR8.2B

Mfr.#: KDZVTFTR8.2B

OMO.#: OMO-KDZVTFTR8-2B-ROHM-SEMI

ZENER DIODES (CORRESPONDS TO AEC
KDZ TR 3.6B

Mfr.#: KDZ TR 3.6B

OMO.#: OMO-KDZ-TR-3-6B-1190

全新原装
KDZ2.0V-RTK

Mfr.#: KDZ2.0V-RTK

OMO.#: OMO-KDZ2-0V-RTK-1190

全新原装
KDZ20V

Mfr.#: KDZ20V

OMO.#: OMO-KDZ20V-1190

全新原装
KDZ24EV-RTK

Mfr.#: KDZ24EV-RTK

OMO.#: OMO-KDZ24EV-RTK-1190

全新原装
KDZ33B

Mfr.#: KDZ33B

OMO.#: OMO-KDZ33B-1190

全新原装
KDZTR9.1B

Mfr.#: KDZTR9.1B

OMO.#: OMO-KDZTR9-1B-ROHM-SEMI

Zener Diodes 9.1 to 10.2V; 40mA 1000mW
KDZVTR33B

Mfr.#: KDZVTR33B

OMO.#: OMO-KDZVTR33B-ROHM-SEMI

Zener Diodes 34.95V 6% 1W 2-Pin PMDU
可用性
库存:
Available
订购:
3500
输入数量:
KDZ18V的当前价格仅供参考,如果您想获得最优惠的价格,请提交查询或直接发送电子邮件至我们的销售团队[email protected]
参考价格(美元)
数量
单价
小计金额
1
US$0.00
US$0.00
10
US$0.00
US$0.00
100
US$0.00
US$0.00
500
US$0.00
US$0.00
1000
US$0.00
US$0.00
从...开始
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